汞中毒怎么用螯合治疗？
How is mercury poisoning treated with chelation?
二巯基丙磺酸钠等螯合剂以多硫或多氮配位结合 Hg²⁺，经尿排出；有机汞（甲基汞）最难清除。
Chelators like DMPS bind Hg²⁺ through multiple S or N donors and excrete it in urine; organic mercury (methylmercury) is hardest to remove.
难度 专业 · 适合 大众
CC BY 4.0 · 已核验 · Verified 2026-08-23
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Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#汞 #螯合 #解毒
晶体场理论中 d 轨道在八面体场中如何分裂？
How do d orbitals split in an octahedral crystal field?
在八面体配体场中，5 个简并 d 轨道分裂为能量较低的 t₂g（dxy、dxz、dyz）和能量较高的 eg（dx²−y²、dz²），分裂能 Δo 决定高/低自旋与配合物颜色。
In an octahedral ligand field the five degenerate d orbitals split into lower-energy t₂g (dxy, dxz, dyz) and higher-energy eg (dx²−y², dz²); the splitting energy Δo governs high/low spin and complex color.
难度 专业 · 适合 高中(15-18)
CC BY 4.0 · 已核验 · Verified 2026-08-23
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Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#晶体场 #配位 #分裂能
金属羰基配合物中 CO 的 π 反馈键是什么？
What is π back-bonding in metal carbonyl complexes?
CO 以其孤对电子向金属空 d 轨道提供 σ 配位（σ 给予），同时金属充满的 d 电子反馈到 CO 的空 π* 反键轨道（π 反馈）。这种协同成键稳定了低氧化态金属并削弱 C−O 键，使 ν(CO) 红移。
CO donates a lone pair into an empty metal d orbital (σ donation) while metal d electrons back-donate into CO's empty π* orbital (π back-bonding). This synergic bonding stabilizes low-oxidation-state metals and weakens the C−O bond, shifting ν(CO) to lower wavenumbers.
难度 专业 · 适合 高中(15-18)
CC BY 4.0 · 已核验 · Verified 2026-08-23
来源 · Source
Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#反馈键 #配位化学 #羰基
为什么一种蓝颜料竟能解重金属中毒？
Why can a blue pigment counteract heavy-metal poisoning?
普鲁士蓝是亚铁氰化铁，人体基本不吸收，却能在肠道结合铊、铯等重金属促其排出，既是颜料也是解毒药。
Prussian blue (iron ferrocyanide) is not absorbed but binds thallium/cesium in the gut, speeding excretion—both pigment and antidote.
难度 专业 · 适合 初中(12-15)
CC BY 4.0 · 已核验 · Verified 2026-08-23
来源 · Source
Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#普鲁士蓝 #解毒 #重金属
配合物中几何异构（顺反）怎样产生？以 MA₂B₂ 或 [Co(NH₃)₄Cl₂]⁺ 为例。
How does geometric (cis-trans) isomerism arise in complexes? Use MA₂B₂ or [Co(NH₃)₄Cl₂]⁺ as example.
在正方形或八面体中，若两个相同配体相邻为顺式、相对为反式，则产生异构体。[Co(NH₃)₄Cl₂]⁺ 有顺式（两 Cl 相邻，具极性）与反式（两 Cl 相对）两种，性质（颜色、偶极、反应活性）不同。
In square-planar or octahedral geometries, two identical ligands can be adjacent (cis) or opposite (trans), giving isomers. [Co(NH₃)₄Cl₂]⁺ exists as cis (Cl adjacent, polar) and trans (Cl opposite) forms differing in color, dipole, and reactivity.
难度 专业 · 适合 高中(15-18)
CC BY 4.0 · 已核验 · Verified 2026-08-23
来源 · Source
Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#几何异构 #顺反 #八面体
什么是Jahn-Teller效应？以[Cu(H₂O)₆]²⁺为例，说明d⁹组态为何使正八面体发生沿z轴的四方拉长畸变，该畸变在能量上有何后果？
What is the Jahn-Teller effect? Taking [Cu(H₂O)₆]²⁺ as an example, explain why a d⁹ configuration distorts a regular octahedron by tetragonal elongation along the z axis, and what the energetic consequence of this distortion is.
Jahn-Teller定理指出：非线性分子处于轨道简并电子态时会自发畸变以解除简并、降低能量。Cu²⁺为d⁹组态，八面体场中eg轨道共三个电子，一个双占、一个单占。沿z轴拉长使dz²下降而dx²-y²升高，被稳定的是双占的dz²轨道，体系总能净降低，简并解除，形成两条较长的轴向键与四条较短的赤道键。
The Jahn-Teller theorem states that a non-linear molecule in an orbitally degenerate electronic state distorts spontaneously to lift that degeneracy and lower its energy. Cu²⁺ is d⁹, and in an octahedral field three electrons occupy the two eg orbitals, one being doubly occupied and the other singly occupied. Elongating along the z axis lowers dz² and raises dx²-y²; because the stabilized dz² holds two electrons, the net total energy decreases, the degeneracy disappears, and the ion ends up with two long axial bonds and four shorter equatorial ones.
难度 专业 · 适合 高中(15-18)
CC BY 4.0 · 已核验 · Verified 2026-11-02
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H. A. Jahn、E. Teller，《简并电子态下多原子分子的稳定性 I. 轨道简并》，Proceedings of the Royal Society A，1937年，第161卷，220–235页，DOI: 10.1098/rspa.1937.0142。
H. A. Jahn and E. Teller, "Stability of polyatomic molecules in degenerate electronic states. I. Orbital degeneracy", Proceedings of the Royal Society A, vol. 161, pp. 220-235, 1937, DOI: 10.1098/rspa.1937.0142.
独立核验依据 · Independent verification: 核验依据 1 CROSSREF 标识 10.1098/rspa.1937.0142：Stability of polyatom
#配位化学 #姜-泰勒效应 #d9组态 #结构畸变
螯合效应为什么使配合物更稳定？
Why does the chelate effect make complexes more stable?
多齿配体取代多个单齿配体时，粒子数增加使熵增（ΔS > 0），按 ΔG = ΔH − TΔS 使 ΔG 更负，平衡强烈偏向螯合物。此外螯合环的成环也提供额外的动力学与热力学稳定。
When a polydentate ligand replaces several monodentate ones, the number of particles increases, raising entropy (ΔS > 0); via ΔG = ΔH − TΔS this makes ΔG more negative, shifting equilibrium strongly toward the chelate. Ring closure adds further thermodynamic and kinetic stability.
难度 专业 · 适合 高中(15-18)
CC BY 4.0 · 已核验 · Verified 2026-08-23
来源 · Source
Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#螯合效应 #熵 #稳定常数
过渡金属配合物为什么有颜色？
Why are transition-metal complexes colored?
d 轨道在配体场中分裂，电子吸收可见光中特定能量发生 d-d 跃迁（能量 ≈ 分裂能 Δ），未被吸收的补色被反射/透射而显色。跃迁被禁阻时颜色较浅，电荷转移跃迁则可产生深色。
Ligand-field splitting of d orbitals lets electrons absorb visible light of a specific energy for d-d transitions (energy ≈ Δ); the unabsorbed complementary color is reflected/transmitted, giving the hue. Largely forbidden transitions are pale, while charge-transfer transitions can be intense.
难度 进阶 · 适合 初中(12-15)
CC BY 4.0 · 已核验 · Verified 2026-08-23
来源 · Source
Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#配合物颜色 #d-d跃迁 #分裂能
什么是单齿配体与多齿配体？
What are monodentate and polydentate ligands?
单齿配体只通过一个配位原子成键，如 H₂O、NH₃、Cl⁻；多齿配体（螯合剂）通过两个及以上原子成键，如乙二胺（双齿）、EDTA（六齿），能形成更稳定的螯合环。
Monodentate ligands bind through one donor atom, e.g., H₂O, NH₃, Cl⁻; polydentate (chelating) ligands bind through two or more atoms, e.g., ethylenediamine (bidentate) and EDTA (hexadentate), forming more stable chelate rings.
难度 进阶 · 适合 初中(12-15)
CC BY 4.0 · 已核验 · Verified 2026-08-23
来源 · Source
Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#配体 #螯合 #齿数
如何确定配合物中中心金属的氧化态？
How do you determine the oxidation state of the central metal in a complex?
把配体按已知电荷（如 Cl⁻ = −1、CN⁻ = −1、中性 H₂O/NH₃ = 0）列出，根据配合物总电荷反推金属电荷。例如 [Fe(CN)₆]⁴⁻ 中 6×(−1)+x = −4，得 Fe 为 +2。
Assign known ligand charges (Cl⁻ = −1, CN⁻ = −1, neutral H₂O/NH₃ = 0) and solve for the metal from the complex's total charge. In [Fe(CN)₆]⁴⁻, 6×(−1)+x = −4 gives Fe as +2.
难度 进阶 · 适合 初中(12-15)
CC BY 4.0 · 已核验 · Verified 2026-08-23
来源 · Source
Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#氧化态 #配体电荷 #配合物
配合物的命名顺序是什么？
What is the naming order for coordination complexes?
先列配体（按字母序或先无机后有机、先阴离子后中性），用倍数词头（di-, tri-）标明个数，再写金属名并括号注明氧化态，如 [Co(NH₃)₆]Cl₃ 称三氯化六氨合钴(III)。内界与外界按离子化合物规则命名。
List ligands alphabetically (or inorganic before organic, anionic before neutral) with prefixes (di-, tri-) for counts, then the metal name with oxidation state in parentheses—e.g., [Co(NH₃)₆]Cl₃ is hexaamminecobalt(III) chloride. Inner and outer spheres follow ionic-compound rules.
难度 进阶 · 适合 初中(12-15)
CC BY 4.0 · 已核验 · Verified 2026-08-23
来源 · Source
Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#命名 #配体 #氧化态
什么是螯合效应？为什么EDTA与钙离子形成的配合物特别稳定？
What is the chelate effect, and why does EDTA form such stable complexes with calcium ions?
螯合效应指多齿配体形成的环状配合物比同类单齿配体配合物更稳定。EDTA以两个氮和四个氧共六个配位原子同时结合金属，一个分子可置换出六到八个配位水，使溶液中自由粒子数明显增加，熵增大成为稳定性的主要来源；五个五元螯环也降低了成环的能量代价。故Ca-EDTA的logK约达10.7，广泛用于水质软化和配位滴定。
The chelate effect is the observation that complexes formed by polydentate ligands are markedly more stable than analogous complexes of comparable monodentate ligands. EDTA binds metals through six donor atoms, two nitrogens and four carboxylate oxygens, so one molecule displaces six to eight coordinated water molecules; the number of freely moving particles rises sharply, making the large positive entropy the dominant source of stability, aided by five strain-free five-membered rings. Consequently the calcium-EDTA complex has logK near 10.7 and is widely used in water softening and complexometric titration.
难度 进阶 · 适合 初中(12-15)
CC BY 4.0 · 已核验 · Verified 2026-11-02
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Shriver & Atkins《无机化学》，Weller 等编著，第6版，牛津大学出版社，2014年
Shriver & Atkins' Inorganic Chemistry, M. Weller et al., 6th ed., Oxford University Press, 2014
独立核验依据 · Independent verification: 核验依据 1 OPENLIBRARY 标识 /works/OL18276456W：Shriver & Atkins' inor
#螯合效应 #配位化学 #熵驱动
维尔纳配位理论的核心观点是什么？
What are the core ideas of Werner's coordination theory?
维尔纳提出金属有两种化合价：主价（氧化态，满足经典化合价）与副价（配位数，由配体满足）。配合物有确定的空间构型，从而解释同分异构与“分子化合物”，奠定了现代配位化学。
Werner proposed metals have a principal valence (oxidation state) and an auxiliary valence (coordination number satisfied by ligands), with definite spatial geometry. This explained isomers and 'molecular compounds', founding modern coordination chemistry.
难度 入门 · 适合 小学高段(9-12)
CC BY 4.0 · 已核验 · Verified 2026-08-23
来源 · Source
Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#维尔纳 #配位数 #构型
配合物中的配位数指什么？
What does coordination number mean in a complex?
配位数是中心原子直接结合的配位原子总数。例如 [Cu(NH₃)₄]²⁺ 配位数为 4，[Fe(CN)₆]⁴⁻ 为 6；单齿配体时配位数等于配体数，多齿配体时小于配体数。
Coordination number is the count of donor atoms directly bonded to the central atom. For example [Cu(NH₃)₄]²⁺ has CN 4 and [Fe(CN)₆]⁴⁻ has CN 6; with monodentate ligands CN equals the ligand count, but with polydentate ligands it is smaller.
难度 入门 · 适合 小学低段(6-8)
CC BY 4.0 · 已核验 · Verified 2026-08-23
来源 · Source
Housecroft & Sharpe,《Inorganic Chemistry》第5版,Pearson,2018
C. E. Housecroft and A. G. Sharpe, Inorganic Chemistry, 5th ed., Pearson, 2018
#配位数 #配位原子 #配合物